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Thread: Calculation Method for Clamping Force needed

  1. #1
    Join Date
    Dec 2018
    Posts
    2

    Question Calculation Method for Clamping Force needed

    I need to understand the calculation method for the clamping force needed depending on the part dimensions, cavity, and machine pressure injection.

    Here is what I have:

    1.- See the part dimensions attached.
    note: dimensions in inches
    Part weight: 46 grs.

    2.- The number of cavities is 4
    3.- The machine pressure injection is 213 Mpa.
    4.- The part material is Nylon 6/6

    Is this data enough to calculate the CF?
    Attached Thumbnails Attached Thumbnails S_D1.jpg   S_D2.jpg  

  2. #2
    Join Date
    Jun 2017
    Location
    Ningbo zhejiang Province China PR
    Posts
    10

    Re: Calculation Method for Clamping Force needed

    I am trying to enclosed a picture, but I do not have the access. Sorry. clamping load =specific. clamping force* project all areas( all parts and runner).

  3. #3
    Join Date
    Feb 2016
    Location
    San Francisco Bay Area, CA
    Posts
    199

    Re: Calculation Method for Clamping Force needed

    I'll generally use 3 - 5 tons per square inch of molded plastic at parting line
    Slightly higher if slides are used
    Ultimately the molded part itself will tell you where tonnage should be - ie run a little faster injection speed/holding pressure as a 'worst case scenario' and just keep coming down on tonnage until you start to see little flash in areas

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