Calculating Intensification Ratio

[Ferry]

Hello,

I can not figure out how to calculate the intensification ratio.
I know the formula is: Ri = Maximum injection (plastic) pressure/maximum hydraulic pressure for the injection unit.

But as example for an Arburg 270
These are the technical data: http://www.arburg.com/fileadmin/redaktion/mediathek/technische_daten/arburg_allrounder_270a_td_680293_en_gb.pdf

Maximum injection (plastic) pressure is 2500, 2000 or 1550 bar depending on the screw diameter.
But what is the hydraulic pressure? Or is that something which only can be done at the machine, not only from the data?

I hope anyone can help me out :D

[brentb]

IR= Area of hydraulic ram (cylinder/ piston) Divided by Area of screw

a 10 sq whatever ram/piston / by a 1 sq whatever screw = 10:1 Intensification Ratio

Hydraulic line pressure X IR = Plastic Pressure

You have 2 rams to deal with Hydraulic (big) and screw,(small)acting as a ram

We are dealing with cross sectional area.

Keep on Molding!

brent

[brentb]

Your Arburg should have come set to show plastic pressure by the way.

KOM

brent

[Suhas]

Ferry,
I think the machine you show here is an electric - in which case IR = 1 (no hydraulics). Please confirm.
Inmost cases, you will see a chart on the machine.
Suhas

[Ferry]

The machine that I used for the technical data was as an example.
But the conclusion will be that it is an electric powered machine.
So for the IR I use 1.

I want to use the IR for the 6 step study.
But for the viscosity curve the IR is a constant in the equation: Viscosity = Peak Injection Pressure X Fill Time X Screw Intensification Ratio.
So the viscosity will change if i change the IR. But the curve won't change.
If I use 1 or 10, my fill time will stay the same. The fill time will be the time where the curve stays constant.

Please correct me if I am wrong.

[Suhas]

Hello Ferry,
You are Correct. The Viscosity will change with the factor but the curve profile will not change.
Suhas